depression=molality*Kf
= gramsunknown*Kf/(molmassunk*.0905)
solve for molmassunk.
Pure glacial acetic acid HC2H3O2 has a freezing point of 16.62 degrees C. Its freezing point depression constant is Kf=3.57 Cm^-1. A solution was made by taking 9.755 g of an unknown non-electrolyte and dissolving it in 90.50 g of glacial acetic acid. The measured freezing point of the solution was 8.64 degrees C. Find the molecular weight of the unknown substance.
1 answer