Asked by CAITLIN GOMEZ
TOTAL PERIMETER OF A TRIANGLE
= 10x +4
A= 3×+1
B= 5x-2
C=?
= 10x +4
A= 3×+1
B= 5x-2
C=?
Answers
Answered by
mathhelper
Assuming that A, B, and C are the sides of the triangle, then
A + B + C = 10x + 4
3x+1 + 5x-2 + C = 10x + 4
C = 10x + 4 - 3x - 5x - 1 + 2
= 2x + 5
A + B + C = 10x + 4
3x+1 + 5x-2 + C = 10x + 4
C = 10x + 4 - 3x - 5x - 1 + 2
= 2x + 5
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