Question

The spinner is divided into equal parts. Use a tree diagram to find the probability that the spinner will land on a consonant both times if the spinner is spun twice.

There are 3 equal parts with the letters E, U, and N

1/9
1/3**
5/9
3/4

Since 3 is an odd number and there are 2 vowels I believe the chances on landing on N is 1/3 due to 2 of the parts being vowels
3 - 2- 1
3 parts
1/3

Answer 1

You are spinning it twice. The spinner has no "memory" of what happened
the first spin as you spin it a second time.
Prob(consonant, then consonant) = (1/3)(1/3) = 1/9

I will attempt to show the tree, difficult in this format

---------------------------------------- start -----------------------------------
---------------------- E --------------------------- U -------------------N ----------------------
EE-----------EU ----------EN ... --UE--------UU---- UN ...-- NE-----NU-------NN

notice there are 9 outcomes, only one, the NN, has both consonants.
so the prob(your event) = 1/9

Answer 2

Thank you!
@mathhelper!