Asked by Lo
A spinner is divided into 5 equal sections numbered 1, 2, 3, 4, and 5. If the spinner is spun and a coin is tossed, what is the probability of getting a tail on the coin and an odd number on the spinner
Answers
Answered by
MathMate
P(tail) = 1/2
P(odd) = P(1)+P(3)+P(5) = 1/5+1/5+1/5=3/5
Joint probability of two independent events
= P(odd)*P(tail)
= 3/5*1/2
= 3/10
P(odd) = P(1)+P(3)+P(5) = 1/5+1/5+1/5=3/5
Joint probability of two independent events
= P(odd)*P(tail)
= 3/5*1/2
= 3/10
Answered by
JJ Buenrostro
P(tail) = 1/2
P(odd) = P(1)+P(3)+P(5) = 1/5+1/5+1/5=3/5
Joint probability of two independent events
= P(odd)*P(tail)
= 3/5*1/2
= 3/10
P(odd) = P(1)+P(3)+P(5) = 1/5+1/5+1/5=3/5
Joint probability of two independent events
= P(odd)*P(tail)
= 3/5*1/2
= 3/10
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