Asked by George
The scale of a pitch is 1cm to 2.5m. If the length was drawn as 5cm, how long is the ground?
Answers
Answered by
mathhelper
sketch a right-angled triangle representing your slope of 2.5/1
with a vertical of 5 and a horizontal of 2
then its hypotenuse is √29
In another similar triangle , let the "ground " be x
and its hypotenuse be 5
x /2 = √29/5
x = 2√29/5 = appr 2.154
in the first triangle the units were metres, in the second they were cm
In my equation, the units would cancel
with a vertical of 5 and a horizontal of 2
then its hypotenuse is √29
In another similar triangle , let the "ground " be x
and its hypotenuse be 5
x /2 = √29/5
x = 2√29/5 = appr 2.154
in the first triangle the units were metres, in the second they were cm
In my equation, the units would cancel
Answered by
correction - mathhelper
Oooops .... My ratio should have been:
x/2 = 5/√29
x = 10/√29
x =1.8569
We could have used trig
from the slope of 2.5/1
tan P = 2.5/1
angle P = 68.1986°
now you want the base side
cos 68.1986 = x/5
x = 5cos68.1986 = appr 1.8569
x/2 = 5/√29
x = 10/√29
x =1.8569
We could have used trig
from the slope of 2.5/1
tan P = 2.5/1
angle P = 68.1986°
now you want the base side
cos 68.1986 = x/5
x = 5cos68.1986 = appr 1.8569
Answered by
oobleck
nice trig, but what does it have to do with a scale drawing?
I think the "pitch" here is a sports field (although quite a small one)
1cm : 2.5m = 5cm : 12.5m
I think the "pitch" here is a sports field (although quite a small one)
1cm : 2.5m = 5cm : 12.5m
Answered by
mathhelper
Was visualizing the pitch of a roof.
getting so tired of trying to make sense of poorly worded questions.
getting so tired of trying to make sense of poorly worded questions.
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