Question
an airplane is travelling at 500km/h due south when it encounters a wind from W45N at 100 km/h.
a. what is the resultant velocity of the airplane?
b. how long will it take for the airplane to travel 1000km?
a. what is the resultant velocity of the airplane?
b. how long will it take for the airplane to travel 1000km?
Answers
Anon
I just figured it out
for a,
the wind is coming from w45N,
so you just do vector addition and then you get E135S... i think.
I will try to describe: the triangle has the 500km/h going south, and then the 100km/h wind pointing east with an angle of 135deg between the 500km/h (plane) and 100km/h (wind).
Then you just do cosine law, so c = sqrt(a^2+b^2-2(a)(b)cos(C)), sqrt(500^2+100^2-2(500)(100)cos(135)) and you should get 575.7km/h as the resultant.
and b,
just do 1000/575, so 1.738 hours.
for a,
the wind is coming from w45N,
so you just do vector addition and then you get E135S... i think.
I will try to describe: the triangle has the 500km/h going south, and then the 100km/h wind pointing east with an angle of 135deg between the 500km/h (plane) and 100km/h (wind).
Then you just do cosine law, so c = sqrt(a^2+b^2-2(a)(b)cos(C)), sqrt(500^2+100^2-2(500)(100)cos(135)) and you should get 575.7km/h as the resultant.
and b,
just do 1000/575, so 1.738 hours.