Asked by S
An airplane is travelling north at 404.0 km/h. Ten minutes later it is travelling west at 433.0 km/h. What is the magnitude of the average acceleration vector in m/s2?
Answers
Answered by
Damon
a = du/dt i + dv/dt j
original u = 0
final u = -433/3.6
original v = 404/3.6 m/s
final v = 0
ten min = 600 s
du/dt = -433/(3.6*600)
dv/dt = -404/(3.6*600)
|a| = sqrt [ (du/dt)^2 + (v/dt)^2 ]
original u = 0
final u = -433/3.6
original v = 404/3.6 m/s
final v = 0
ten min = 600 s
du/dt = -433/(3.6*600)
dv/dt = -404/(3.6*600)
|a| = sqrt [ (du/dt)^2 + (v/dt)^2 ]
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