initial momentum north = final momentum north
so
6,000*5 = 10,000* Vn
same for west
4,000*15 = 10,000* Vw
speed = s = sqrt(Vn^2+Vw^2)
tan angle north of west = Vn/Vw
initial Ke=(1/2)[6000*25+4,000*225)
final Ke = (1/2)(10,000)s^2
A 6000kg truck travelling north at 5m/s collides with a 4000kg truck moving west at 15m/s,if the two trucks remain locked together after collision,find (a)with what speed and in what direction do they move immediately after collision?(b)what is the lost of kinetic energy of the two trucks after collision?
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Very wonderful and intelligent questions and genius solution
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