Asked by ChengJun Sun
A railway truck travelling along a level track at 5.0 m s−1
collides with a truck of twice the
mass moving in the same direction at 2.5 m s−1
. The trucks couple together and continue
moving. Calculate
(i) the final speed of the combined trucks, and
(ii) the percentage of the kinetic energy lost in the collision.
collides with a truck of twice the
mass moving in the same direction at 2.5 m s−1
. The trucks couple together and continue
moving. Calculate
(i) the final speed of the combined trucks, and
(ii) the percentage of the kinetic energy lost in the collision.
Answers
Answered by
oobleck
(i) conserve momentum
m*5 + 2m*2.5 = (m+2m)v
(ii) before: 1/2 (m*5^2 + 2m*2.5^2)
after: 1/2 (m+2m)v^2
lost = before-after
%lost = lost/before
m*5 + 2m*2.5 = (m+2m)v
(ii) before: 1/2 (m*5^2 + 2m*2.5^2)
after: 1/2 (m+2m)v^2
lost = before-after
%lost = lost/before
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