Asked by thobani
a motorboat traveling 5m/s, EAST encounters a current traveling 2.5m/s North, in what direction should a boat travel so to land directlyat the opposite side of the riverbank?
Answers
Answered by
Anonymous
I assume East is straight across.
boat propulsion speed = 5 in direction X degrees south of East
5 sin X = 2.5
sin X = 2.5 / 5 = 0.50
X = 30 degrees South of East
by the way East speed made good across = 5 cos 30
boat propulsion speed = 5 in direction X degrees south of East
5 sin X = 2.5
sin X = 2.5 / 5 = 0.50
X = 30 degrees South of East
by the way East speed made good across = 5 cos 30
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