Question
A motorboat traveling a distance of 225 miles in 5 hours while traveling with the current. Against the current, the same trip took 9 hours. Find the rate of the boat in calm water and the rate of the current.
rate of boat mph
rate of current mph
rate of boat mph
rate of current mph
Answers
Let c=current speed, and
b=boat speed in still water.
Speed with current = 225/5=45 mph
Speed against current = 225/9=25 mph,
Set up equations:
b+c=45
b-c=25
Solve for b and c.
By the way, when you know the sum and difference of two variables, the variable with the larger value equals (sum+difference)/2 and the variable with the smaller value is (sum-difference)/2.
No need to solve for a system of equations.
b=boat speed in still water.
Speed with current = 225/5=45 mph
Speed against current = 225/9=25 mph,
Set up equations:
b+c=45
b-c=25
Solve for b and c.
By the way, when you know the sum and difference of two variables, the variable with the larger value equals (sum+difference)/2 and the variable with the smaller value is (sum-difference)/2.
No need to solve for a system of equations.
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