Question

Cody’s motorboat took 3 hr to make a trip downstream with a 6-mph current. The return trip against the same current took 5 hr. Find the speed of the boat in still water
Time= distance*velocity

3=d*(vb+vs)
5=d(Vb-vs)

3/d= vb+Vs
5/d=Vb-Vs

add the equations

3/d + 5/d=2Vb

5d+3d=30Vb
solve for Vb
speed of boat in still water ---- x mph

distance going upstream = 5(x-6)
distance going downstream = 3(x+6)

Are the distances not equal ?

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