Question

A block is pushed across a horizontal surface with a
coefficient of kinetic friction of 0.15 by applying a
150 N horizontal force.
The block accelerates at the rate of 2.53 m/s^2.
Find the mass of the block.

I have m*2.53 = 150 - 0.15*m*9.81 which I think is right, but I'm not sure how to get m from that.

Answer 1

I should say the original equation I got that from is this:
Fnet = Fa - Ff
ma = Fa - μkFn

Answer 2

nvm I think I got it:
2.53m = 150-(1.4m)
2.53m + 1.4m = 150
4m = 150
4m/4 = 150/4
m = 37.5kg