Asked by Anonymous
A block of mass 10kg moves horizontal with speed 1.5m/s .if constant vertical force 10N acts,the displacement of block from application of force at end of 4second is?
Answers
Answered by
bobpursley
the horizontal speed continues, so the horizontal displacement is 6m.
vertical displacement is
d=vi*t+1/2 a t^2 where vi=0, a= force/mass=10/10=1m/s^2
d= 1/2 *1*16=8m
displacment = 6horizontal+8up
and that is a 3,4,5 triangle, so the magnitude is 10 at an angle of arctan(4/3)
vertical displacement is
d=vi*t+1/2 a t^2 where vi=0, a= force/mass=10/10=1m/s^2
d= 1/2 *1*16=8m
displacment = 6horizontal+8up
and that is a 3,4,5 triangle, so the magnitude is 10 at an angle of arctan(4/3)
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