Asked by Eyosias
A block of mass 10kg is pulled horizontally by a force of 75N that makes an angle of 37° to the horizontal whose coefficient of friction is 0.4 . what is the acceleration of the block
Answers
Answered by
Henry
M*g = 10kg * 9.8N/kg = 98 N. = Wt. of
block.
Fn = M*g - Fap*sinA = 98 - 75*sin37 =
52.9 N.
Fk = u*Fn = 0.4 * 52.9 = 21.15 N. = Force of kinetic friction.
a = (Fap*Cos37-Fk)/M =
(75*Cos37-21.15)/10 =
block.
Fn = M*g - Fap*sinA = 98 - 75*sin37 =
52.9 N.
Fk = u*Fn = 0.4 * 52.9 = 21.15 N. = Force of kinetic friction.
a = (Fap*Cos37-Fk)/M =
(75*Cos37-21.15)/10 =
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