Asked by Jimmy

A 10kg block is attached to a massless cord that doesn't stretch or sag which is rapped around a disc like wheel, m=5Kg, I= (1/2)mR^2. If the block is allowed to drop straight down held back only by the rotation of the wheel:

1. What is the tension of the rope?
2. What is the acceleration of the block?

Answers

Answered by bobpursley
The force on the rope is tension, which is equal to mg-ma

But this same tension is spinning the wheel:

angularacceleration=Tension/I
a/R=Tension/I

aI=R(mg-ma)
solve for a, then you have it.

check my thinking.
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