work= force.distance= 10*2=20n
friction=force.distance=.4*10*cos180=
remember the dot product means times the cosine of the angle between force and distance. In frictions case, the force opposes the displacement (180 degrees)
A block is pushed 2 m along a fixed horizontal surface by a horizontal force of 10 N. The opposing force of friction is 0.4 N
(a)How much work is done by the 10 N force?
(b)what is the work done by the friction force
1 answer
1 answer