Asked by M
If angle X is an acute angle with sinX=3/5, what is the value of secX?
45
52
53
54
45
52
53
54
Answers
Answered by
mathhelper
given that sinX=3/5 and knowing that sinx = opposite/hypotenuse or y/r
we know from x^2 + y^2 = r^2
x^2 + 3^2 = 5^2
x^2 = 16
x = +4, since you said x was acute
since sec x = 1/cosx = 1/(4/5) = 5/4
all given answers are incorrect, it looks they could be choices for angles
but even that is wrong, since X would be appr 37°
we know from x^2 + y^2 = r^2
x^2 + 3^2 = 5^2
x^2 = 16
x = +4, since you said x was acute
since sec x = 1/cosx = 1/(4/5) = 5/4
all given answers are incorrect, it looks they could be choices for angles
but even that is wrong, since X would be appr 37°
Answered by
oobleck
that's because M doesn't know how to include a virgule in fractions.
I think choice D was meant to be 5/4
I think choice D was meant to be 5/4
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