Asked by zein shion
An arrow is shot at 30.0° angle with the horizontal. It has a velocity of 49 m/s.
a. How high will it go?
b. What is the total flight time (between launch and touching the ground) of the object?
c. What horizontal distance will the arrow travel?
a. How high will it go?
b. What is the total flight time (between launch and touching the ground) of the object?
c. What horizontal distance will the arrow travel?
Answers
Answered by
Anonymous
Vi = 49 sin 30 = 49/2 initial speed up
v = Vi - g t
v = 0 at top
so
time at top = 49 / 2 g
so total time = 49 / g
u= 49 cos 30
range = u * total time
v = Vi - g t
v = 0 at top
so
time at top = 49 / 2 g
so total time = 49 / g
u= 49 cos 30
range = u * total time
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.