Question
I shot the first arrow
Into the air with a speed of 10 m/sec , 1 second later I shot the 2nd arrow into the air with a speed of 15 m/sec.
Will they meet? If so, where?
how do i solve this?
Into the air with a speed of 10 m/sec , 1 second later I shot the 2nd arrow into the air with a speed of 15 m/sec.
Will they meet? If so, where?
how do i solve this?
Answers
Steve
you know the height function, so set them equal. Let's use g=10 for convenience:
10t-5t^2 = 15(t-1)-5(t-1)^2
t = 4/3
that is, 1/3 s after the 2nd arrow takes off.
You can figure the height, I guess.
10t-5t^2 = 15(t-1)-5(t-1)^2
t = 4/3
that is, 1/3 s after the 2nd arrow takes off.
You can figure the height, I guess.