Asked by Anonymous
Kenny had some money. He bought 8 cups of water and 2 cups of chocolate milk with 4/5 of his money. The cost of a cup of chocolate milk is 6 times as much as a cup of water. How many more cups of water can he buy with his remaining money?
Answers
Answered by
mathhelper
cost of cup of water ---- x
cost of cup of cmilk = 6x
cost of ingredients = 8x + 2(6x) = 20x
this is 4/5 of his money, so he has 1/5 of money left
or he has (1/5)(20x) or 4x left
each cup of water costs x
so he can still get 4x/x or 4 cups of water.
That's some weird cost for water!
cost of cup of cmilk = 6x
cost of ingredients = 8x + 2(6x) = 20x
this is 4/5 of his money, so he has 1/5 of money left
or he has (1/5)(20x) or 4x left
each cup of water costs x
so he can still get 4x/x or 4 cups of water.
That's some weird cost for water!
Answered by
Anonymous
Or 5
Answered by
Anonymous
Let, cost of cup of water = x, cost of cup of choc milk = 6x
8 * x + 2 * 6x = 4/5 of money
4/5 of money = 8x + 12x = 20x
Remaining money = 1/5 of money = 20x/4 = 5x
∴ Kenny can buy 5 more cups of water with remaining money.
8 * x + 2 * 6x = 4/5 of money
4/5 of money = 8x + 12x = 20x
Remaining money = 1/5 of money = 20x/4 = 5x
∴ Kenny can buy 5 more cups of water with remaining money.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.