Asked by Kaur

find the absolute maximum and absolute minimum values of the function
f(x)=x . root(32-x²) on [-4,4]
Answered by oobleck
f'(x) = 0 at x = 4
f(-4) = f(4) = 4
f(0) = 0
so the
abs max is 4
abs min is 0
Answered by oobleck
oops. f(-4) = -4, so
abs min is -4 at x = -4
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