find the absolute maximum and absolute minimum values of the function

Question

f(x)=x . root(32-x²) on [-4,4]

Answer 1

f'(x) = 0 at x = 4
f(-4) = f(4) = 4
f(0) = 0
so the
abs max is 4
abs min is 0

Answer 2

oops. f(-4) = -4, so
abs min is -4 at x = -4