g'(x) = x/4 - 2x^(-1/2) = x/4 - 2/√x
= 0 for a max/min
x/4 = 2/√x
x^(3/2) = 8
x = 8^(2/3) = 4
then f(4) = 2 - 4(2) = -6
for endpoints:
f(0) = 0
f(9) = 81/8 - 12 = -15/8 = -1.875
so within the given domain, the maximum function value is 0 , when x = 0
Find the absolute maximum value and the absolute minimum value,
g(x)=1/8 x^2 - 4 x^(1/2) on [0, 9]
1 answer
1 answer