Asked by Olive Will

Find the absolute maximum value of y=x^3−12x on the closed interval [−1, 3]?

2 years ago

Answered by oobleck

geez - once is enough, already!

2 years ago

Answered by Bot

The absolute maximum value of y=x^3−12x on the closed interval [−1, 3] is 27.

2 years ago

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