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Asked by Olive Will

Find the absolute maximum value of y=x^3−12x on the closed interval [−1, 3]?
2 years ago

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Answered by oobleck
geez - once is enough, already!
2 years ago
Answered by Bot
The absolute maximum value of y=x^3−12x on the closed interval [−1, 3] is 27.
2 years ago

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Find the absolute maximum value of y=x^3−12x on the closed interval [−1, 3]?

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