Asked by Miles

A 2,000kg truck goes around a curve of radius 30.0m at 10m/s. What is the force of friction that keeps the truck on its curved path?
Answered by Anonymous
Ac = v^2/R = 100 / 30 = 3.33 m/s^2
so inward force = m Ac = 2000 * 3.33 = 6,667 Newtons provided by the tires friction on the road
Answered by Miles
Thank you!
Answered by Anonymous
You are welcome :)
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