Asked by nikkie
A 10,000kg truck traveling 5m/s collides with a 1,500 kg Volkswagen traveling in the opposite direction at 14 m/s after the collision the truck and Volkswagen stick together. A) what is the final speed and direction of the mess immediately after the collision? (don't foget to define a positative direction) B) how much energery was lost?(heat, sound, vibrations and other etc) during the collision. (Hint calculate the KE of each vechile before and after the collision.
Answers
Answered by
Henry
A. m1*V-m2*V2 = 10,000*5-1,500*14=29,000
m1*V+m2*V = 29,000
10,000*V + 1500*V = 29000
11,500V = 29000
V = 2.52 m/s. In the direction of the
truck.
B. KE1 = 0.5m1*V1^2 = 0.5*10,000*5^2 =
125,000 J. = 125 kJ. Before collision.
KE1 = 0.5*m1*V^2 = 0.5*10,000*2.52^2 = 31,752 J. = 31.75 kJ. After collision.
125-31.75 = 93.25 kJ. Lost during collision.
KE2 = 0.5*m2*V2^2 = 0.5*1500*14^2 = 147000 J. = 147 kJ. Before collision.
KE2 = 0.5m*V^2 = 0.5*1500*2.52^2 = 4763 J. = 4.763 kJ. After collision.
147 - 4.763 = 142 kJ. Lost during collision.
93.25kJ + 142kJ = 235 kJ = KE lost
during collision.
m1*V+m2*V = 29,000
10,000*V + 1500*V = 29000
11,500V = 29000
V = 2.52 m/s. In the direction of the
truck.
B. KE1 = 0.5m1*V1^2 = 0.5*10,000*5^2 =
125,000 J. = 125 kJ. Before collision.
KE1 = 0.5*m1*V^2 = 0.5*10,000*2.52^2 = 31,752 J. = 31.75 kJ. After collision.
125-31.75 = 93.25 kJ. Lost during collision.
KE2 = 0.5*m2*V2^2 = 0.5*1500*14^2 = 147000 J. = 147 kJ. Before collision.
KE2 = 0.5m*V^2 = 0.5*1500*2.52^2 = 4763 J. = 4.763 kJ. After collision.
147 - 4.763 = 142 kJ. Lost during collision.
93.25kJ + 142kJ = 235 kJ = KE lost
during collision.
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