Asked by Jake
Fe2O3 + 3H2 → 2Fe + 3H2O
Calculate the mass of iron produced when 450.0 grams of iron (III) oxide react with hydrogen gas.
If you can please show me the work so I can learn how to do it
Calculate the mass of iron produced when 450.0 grams of iron (III) oxide react with hydrogen gas.
If you can please show me the work so I can learn how to do it
Answers
Answered by
Anonymous
2 Fe = 2 * 56 = 112 grams / 2 mols
3 O = 3 * 16 = 48 g / 3 mols
so
Fe2O3 = 160 g/mol
so
450 g * ( 1 mol / 160 g) = 2.81 mols of iron oxide
That will give me 2 * 2.81 = 5.63 mols of Fe
5.63 * 56 g/mol = 315 grams of Fe
3 O = 3 * 16 = 48 g / 3 mols
so
Fe2O3 = 160 g/mol
so
450 g * ( 1 mol / 160 g) = 2.81 mols of iron oxide
That will give me 2 * 2.81 = 5.63 mols of Fe
5.63 * 56 g/mol = 315 grams of Fe
Answered by
DrBob222
The work by Anonymous is quite right and is presented very well. Here is a set of instructions that will work any stoichiometry problem.
Step 1. Write and balance the equation.
Step 2. Convert what you have into moles. moles = grams/molar mass OR if it is a solution then moles = molarity x liters or M x L = ?
Step 3. Using the coefficients, as Anonymous did above, convert moles of what you have to moles of what you want.
Step 4. If you want grams, then grams = moles x molar mass = ?
Good luck.
Step 1. Write and balance the equation.
Step 2. Convert what you have into moles. moles = grams/molar mass OR if it is a solution then moles = molarity x liters or M x L = ?
Step 3. Using the coefficients, as Anonymous did above, convert moles of what you have to moles of what you want.
Step 4. If you want grams, then grams = moles x molar mass = ?
Good luck.
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