Asked by Marty
6ClO2 + 3H2O -> 5HClO3 + HCl
a) If 71g of ClO2 is mixed with 19g of water, what is the limiting reactant?
b) What mass of HClO3 is expected in part (a)?
c) How many molecules of HCl are expected in part (a)?
I completed part a and b but got stuck on part c. Help!
a) If 71g of ClO2 is mixed with 19g of water, what is the limiting reactant?
b) What mass of HClO3 is expected in part (a)?
c) How many molecules of HCl are expected in part (a)?
I completed part a and b but got stuck on part c. Help!
Answers
Answered by
DrBob222
It would be easier to show you if you showed your work for a and b but I'll try to help not knowing exactly what you have done so far.
You know the limiting reagent. Convert mols of the limiting reagent, whichever it is, to mols HCl produced. Use the coefficients in the balanced equation for the conversion. Now that you know mols HCl, remember that 1 mol of anything contains 6.02 x 10^23 molecules so use that number to convert to number of molecules.
You know the limiting reagent. Convert mols of the limiting reagent, whichever it is, to mols HCl produced. Use the coefficients in the balanced equation for the conversion. Now that you know mols HCl, remember that 1 mol of anything contains 6.02 x 10^23 molecules so use that number to convert to number of molecules.
Answered by
Marty
That helps!
Thanks!
Thanks!
Answered by
Lele
1xHcl/6.02XE1023=6.056478405x1023
Answered by
Lele
i dont know pls help
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.