Asked by Quinn
2Fe+3H2O→Fe2O3+3H2
If 1.24 mol of water react, how many g of iron(III) oxide would be produced?
I know that the answer to this is 66.0 g but I don't understand how to solve it.
If 1.24 mol of water react, how many g of iron(III) oxide would be produced?
I know that the answer to this is 66.0 g but I don't understand how to solve it.
Answers
Answered by
Steve
It takes 3 moles of H2O to produce 1 mole of Fe2O3
so, since you have 1.24 moles of H20, you will get 0.413 moles of Fe2O3.
So, how many grams is that?
so, since you have 1.24 moles of H20, you will get 0.413 moles of Fe2O3.
So, how many grams is that?
Answered by
Quinn
I'm sorry, I don't understand the next step.
Answered by
DrBob222
mols = grams/molar mass. You have mols and you can calculate molar mass; substitute and solve for grams.
Answered by
Steve
Fe2O3 has 2 atoms of Fe (55.845 g/mol)
and 3 atoms of O (16g/mol)
so, a mole of Fe2O3 is 2*55.845 + 3*16 = 159.69 grams
You have only 0.413 moles = 0.413 * 159.69 = 65.95 grams
or 66.0 if you round to the nearest 0.1 gram.
and 3 atoms of O (16g/mol)
so, a mole of Fe2O3 is 2*55.845 + 3*16 = 159.69 grams
You have only 0.413 moles = 0.413 * 159.69 = 65.95 grams
or 66.0 if you round to the nearest 0.1 gram.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.