Asked by Akhigbe
A concrete block of mass 25kg is placed on a wooden plank inclined at an angle of 32° to the horizontal.calculate the force parallel to the inclined plane that will keep the block at rest of the coefficient of friction between the block and the plank is 0.45
Answers
Answered by
R_scott
25 kg * g * cos(32º) * .45 = ? Newtons
use 9.8 m/s^2 for g
use 9.8 m/s^2 for g
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