Asked by Blessing

A concrete block of mass 35kg is pulled along a horizontal floor with the aid of a rope inclined at an angle of 30 degrees to the horizontal. If the coefficient of the friction is 0.75. Calculate the force required to move the block over the floor
Answered by henry2,
M*g = 35*9.8 = 343 N. = Wt. of block. = Normal force, Fn.
Fs = u*Fn = 0.75*343 = 257.3 N. = force of starting friction.

F*Cos30 - Fs = M*a.
F*Cos30 - 257.3 = 35*0.







n
Answered by Halimat
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Answered by Halimat
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