Asked by mclanee
a 5.0kg concrete block accelerates down a 34 degree slope at 4.2 m/s^2. Find the coefficient of friction between the block and the slope.
The component of weight down the slope is mg*SinTheta. The component of weight perpendicular to the slope is mg CosTheta.THe friction force then opposing motion is mu*mg*cosTheta.
Net force down= mgSinTheta-mg*mu*CosTheta
but net force= mass*acceleration
set them equal, and solve for mu.
The component of weight down the slope is mg*SinTheta. The component of weight perpendicular to the slope is mg CosTheta.THe friction force then opposing motion is mu*mg*cosTheta.
Net force down= mgSinTheta-mg*mu*CosTheta
but net force= mass*acceleration
set them equal, and solve for mu.
Answers
Answered by
Addis
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