Asked by Temitope
Slover the equation x2-7x-5=0.using the completing the square method your answer in 3s.f
Answers
Answered by
mathhelper
x^2 - 7x - 5 = 0
x^2 - 7x + 49/4 = 5 + 49/4
(x - 7/2)^2 = 69/4
x - 7/2 = ± √69/2
x = ( 7 ± √69)/2
x^2 - 7x + 49/4 = 5 + 49/4
(x - 7/2)^2 = 69/4
x - 7/2 = ± √69/2
x = ( 7 ± √69)/2
Answered by
Anonymous
x2-7x-5=0
x^2 - 7 x = 5
x^2 - 7 x +(7/2)^2 = 5 + (7/2)^2
(x -7/2)^2 = 5 + 49/4 = 17.25
x - 7/2 = +/- sqrt(17.25)
x = 3.5 +/- 4.15
x^2 - 7 x = 5
x^2 - 7 x +(7/2)^2 = 5 + (7/2)^2
(x -7/2)^2 = 5 + 49/4 = 17.25
x - 7/2 = +/- sqrt(17.25)
x = 3.5 +/- 4.15
Answered by
Vallari
Good
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