Question
Using the equation below as a model, fill in numbers in the place of a and b to create a rational equation that has an extraneous solution.
x+a/ax=b/x
Part 1. Show all work to solve for x in the equation and check the solution.
Part 2. Explain how to identify the extraneous solution and what it means.
x+a/ax=b/x
Part 1. Show all work to solve for x in the equation and check the solution.
Part 2. Explain how to identify the extraneous solution and what it means.
Answers
Did you mean it the way you typed it, then by the order of operations....
x + 1x= b/x, since a/a = 1
2x = b/x
2x^2 = b
x^2 = √(b/2)
for extraneous roots, a can be any non-zero number, and b < 0
If you meant:
(x+a)/(ax) = b/x
x^2 + ax = abx
x^2 + ax - abx = 0
x^2 + x(a - ab) = 0
for extraneous roots the discriminant < 0
(a-ab)^2 - 4(1)(0) < 0
(a - ab)^2 < 0
but any square is ≥ 0, so no combination of a and b will produce extraneous roots
if you meant:
((x+a)/a)(x) = b/x
...
you try it
x + 1x= b/x, since a/a = 1
2x = b/x
2x^2 = b
x^2 = √(b/2)
for extraneous roots, a can be any non-zero number, and b < 0
If you meant:
(x+a)/(ax) = b/x
x^2 + ax = abx
x^2 + ax - abx = 0
x^2 + x(a - ab) = 0
for extraneous roots the discriminant < 0
(a-ab)^2 - 4(1)(0) < 0
(a - ab)^2 < 0
but any square is ≥ 0, so no combination of a and b will produce extraneous roots
if you meant:
((x+a)/a)(x) = b/x
...
you try it
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