Asked by Nseobong
A g.p has 6 terms. If the third and fourth term are 28 and_56 respectively find the first term, the sum of the g.p and the product of the tenths and 20 term
Answers
Answered by
mathhelper
Just translate the English into Math.
"If the third and fourth term are 28 and_56 respectively "
ar^2 = 28
ar^3 = 56
divide the second equation by the first.
r = 56/28 = 2
from ar^2 = 28
a(4) = 28
a = 7
Sum(6) = a(r^6 - 1)/(r-1)
= 7(2^6 - 1)/1= 441
You said, the GP has 6 terms, why are are finding stuff about
term10 and term20??
anyway .....
term(10) = 7(2^9)
term(20) = 7(2^19)
product = 49(2^28) , write it in scientific notation or whatever way you want
"If the third and fourth term are 28 and_56 respectively "
ar^2 = 28
ar^3 = 56
divide the second equation by the first.
r = 56/28 = 2
from ar^2 = 28
a(4) = 28
a = 7
Sum(6) = a(r^6 - 1)/(r-1)
= 7(2^6 - 1)/1= 441
You said, the GP has 6 terms, why are are finding stuff about
term10 and term20??
anyway .....
term(10) = 7(2^9)
term(20) = 7(2^19)
product = 49(2^28) , write it in scientific notation or whatever way you want
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