Asked by Anonymous
                 Find the point on the curve y = gent line is parallel to the line y = x
√ y = x to y = x
x where the tan-8 .
(b) On the same axes, plot the curve y = √
√ x, the line
8 , and the tangent line to y = x that is parallel 8 .
            
            
        √ y = x to y = x
x where the tan-8 .
(b) On the same axes, plot the curve y = √
√ x, the line
8 , and the tangent line to y = x that is parallel 8 .
Answers
                    Answered by
            oobleck
            
    proofread your post and fix it, ok?
also, not sure how to interpret
y = x
√ y = x to y = x
and what is "tan-8"? tan<sup><sup>-1</sup></sup>8 ?
For (b), I'll guess you want
where the tangent line to y=√x is parallel to y=x
If so, then since the slope of y=x is 1,
y' = 1/(2√x)
so
1/(2√x) = 1 at x = 1/4
that would be at the point (1/4, 1/2)
see
www.wolframalpha.com/input?i=plot+y%3D%E2%88%9Ax%2C+y%3Dx%2B1%2F4
    
also, not sure how to interpret
y = x
√ y = x to y = x
and what is "tan-8"? tan<sup><sup>-1</sup></sup>8 ?
For (b), I'll guess you want
where the tangent line to y=√x is parallel to y=x
If so, then since the slope of y=x is 1,
y' = 1/(2√x)
so
1/(2√x) = 1 at x = 1/4
that would be at the point (1/4, 1/2)
see
www.wolframalpha.com/input?i=plot+y%3D%E2%88%9Ax%2C+y%3Dx%2B1%2F4
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