Asked by kartik
Find the point P on the curve y2 = 4ax which is nearest to the point
(11a, 0).
(11a, 0).
Answers
Answered by
Steve
the distance z from (x,y) to (11a,0) is
z = √((x-11a)^2 + y^2)
= √((x-11a)^2 + 4ax)
= √(x^2-18ax+121a^2)
dz/dx = (x-9a)/√(x^2-18ax+121a^2)
dz/dx=0 when x = 9a
So, P is (9a,6a)
z = √((x-11a)^2 + y^2)
= √((x-11a)^2 + 4ax)
= √(x^2-18ax+121a^2)
dz/dx = (x-9a)/√(x^2-18ax+121a^2)
dz/dx=0 when x = 9a
So, P is (9a,6a)
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