Question
Hi, same ques. again
1/3log(base5) 3x + log(base5) 4=3
If the starting is this: log(base5)3x^1/3+log(base5)4=3
What would be the rest?
1/3log(base5) 3x + log(base5) 4=3
If the starting is this: log(base5)3x^1/3+log(base5)4=3
What would be the rest?
Answers
oobleck
again? Follow the same steps
log(3x)^(1/3) + log4 = 3
1/3 log(3x) + log4 = 3
now proceed as has been shown twice already
log(3x)^(1/3) + log4 = 3
1/3 log(3x) + log4 = 3
now proceed as has been shown twice already
Jack
Thanks, oobleck
Your calc. made sense
no need to redo it.
Thx..........................................
Your calc. made sense
no need to redo it.
Thx..........................................