Asked by King

Solve equation
2log10^x - 3log10^2 + log10^32 = 2
Answered by Damon
log 10^2x - log10^6 + log 10^32 = 2
log 10^ (2x*26) = 2
52 x = 10^2 = 100
x = 100/52 = 25/13
Answered by R_scott
10^(2x) * 10^32 / 10^6 = 10^2

2x + 32 - 6 = 2

x = -12
Answered by Lucy
Helpful thanks