Question
The AM of two numbers exceeds their positive GM by 10 and the first number is 9 times the second number, find the two numbers
Answers
oobleck
AM = (9x+x)/2
GM = √(9x*x)
so now you have
5x = 3x+10
Now finish it off
GM = √(9x*x)
so now you have
5x = 3x+10
Now finish it off