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Asked by BRUN ALLAN OTIENO

The AM of two numbers exceeds their positive GM by 10 and the first number is 9 times the second number, find the two numbers
3 years ago

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Answered by oobleck
AM = (9x+x)/2
GM = √(9x*x)
so now you have
5x = 3x+10
Now finish it off
3 years ago
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The AM of two numbers exceeds their positive GM by 10 and the first number is 9 times the second number, find the two numbers

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