Asked by CookieCrumbs

Ana's age exceeds one-fifth of her dad's age by seven. In 19 years, her dad will be twice as old as her. How old is her dad now?

Pls, help! I think it is 17.5 or 19, but I'm not sure. :(
Answered by CookieCrumbs
Pls Help!
Answered by R_scott
A = d/5 + 7 ... 5A = d + 35 ... d = 5A - 35

2(A + 19) = d + 19 ... 2A + 38 = d + 19 ... d = 2A + 19

substituting ... 5A - 35 = 2A + 19

solve for A , then substitute back to find d
Answered by mathhelper
Now:
dad's age --- x
Ana's age --- y
y - x/5 = 7
y = x/5 + 7
Ana's age ---- (1/5)x + 7

19 years from now:
dad = x+19
Ana's age = (1/5)x + 7 + 19 = x/5 + 26

x+19 = 2(x/5 + 26)
x+19 = 2x/5 + 52
times 5, (don't like fractions)
5x + 95 = 2x + 260
3x = 165
x = 55

Her dad is now 55

check:
now her dad is 55
Ana is now 55/5 + 7 or 18 years

in 19 years:
dad is 74+19 = 74
ana = 18 + 19 = 37 , YES, here dad will be twice as old
Answered by Bosnian
a = Ana"s present age

d = dad's present age

Ana's age exceeds one-fifth of her dad's age by seven means:

a = d / 5 + 7

After 19 years Ana’s age will be a + 19 and Dad’s age will be d + 19

In 19 years, her dad will be twice as old as her means:

d + 19 = 2 ( a + 19 )

Since a = d / 5 + 7 replace

a with d / 5 + 7 in this equation

d + 19 = 2 ( d / 5 + 7 + 19 )

d + 19 = 2 ( d / 5 + 26 )


d + 19 = 2 d / 5 + 52

Subtract 19 to noth sides

d = 2 d / 5 + 33

Subtract 2 d / 5 to both sides

d - 2 d / 5 = 33

5 d / 5 - 2 d / 5 = 33

3 d / 5 = 33

Divide both sides by 3

d / 5 = 11

d = 55

a = d / 5 + 7 =

55 / 5 + 7 = 11 + 7 = 18

Ana is 18 yrs , Dad is 55 yrs old









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