Asked by seraphine

the sum of two numbers exceeds their product by one. their differences is equal to their product less five . find the two numbers
Answered by nile
let n-1st no.
m-2nd no.
n+m=(nXm)+1-----eqtn. 1
n-m=(nXm)-5-----eqtn. 2

solve by elimination

n+m=(nXm)+1-----eqtn. 1
-
n-m=(nXm)-5-----eqtn. 2
________________________________
2m=6

m=3
subst. to eqtn 1 or 2

n+m=(nXm)+1-----eqtn. 1
n+3=3n+1
-2n=-2
n=1

therefore, the nos. are 3 and 1


Answered by Wendy
True and thank you for the answer
Answered by Vivian
Thanks
Answered by Audry
true and thanks for the answer
Answered by Abel Kemboi
Right
Answered by Samuel
Not true thanks
Answered by Anonymous
correct
Answered by tanaka
i don't understand please help me
Answered by Jeremy
Well done
Answered by Brian
Yes
Answered by Samwel
Thank u
Answered by Rose
Love your way of approaching the question but I wish you would solve the equation for the rest of us who don't know how
Answered by Tessy
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Answered by Abigael
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Answered by Abby
I asked I did not say I know it
Answered by Abby
I don't understand pliz
Answered by Abi
Thanks
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