Asked by Kaur
Consider a function f(x) = x^2 + e^x then f'(f(0)) is equal to
Answers
Answered by
mathhelper
f ' (x) = 2x + e^x
since f(0) = 0 + e^0 = 1
f'(f(0)) = f'(1) = 2 + e
since f(0) = 0 + e^0 = 1
f'(f(0)) = f'(1) = 2 + e
Answered by
Kaur
Thanks, I got the same
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