A simple pendulum has a 2.5 kg mass attached to a string that is 0.65 m in length. If the pendulum is released at an angle of 35° with the horizontal, then the period of the pendulum is seconds.

To find the period of a simple pendulum, we can use the formula:

T = 2π * √(L/g)

Where:
T = Period of the pendulum
π = Pi (approximately 3.14159)
L = Length of the pendulum
g = Acceleration due to gravity (approximately 9.8 m/s²)

Given that the length of the pendulum is 0.65 m, we can substitute the values into the formula:

T = 2π * √(0.65/9.8)

Now, we can solve the equation step-by-step:

1. Calculate the square root of (0.65/9.8):
√(0.65/9.8) ≈ 0.08049

2. Multiply by 2π:
2π * 0.08049 ≈ 0.5066

Therefore, the period of the pendulum is approximately 0.507 seconds.