Asked by Johnathan
An observer spots a plane travelling at an altitude of 4000m with an angle of elevation of 30 degrees at 11:59 am. At noon, the plane is directly over him. What is the speed of the plane m/s?
Help
Help
Answers
Answered by
mathhelper
Did you make a sketch?
At 11:59 , let the horizontal distance of the plane from the observer be x m
then tan30° = 4000/x
x = 4000/tan30° = 6928.203... m
so in 1 min (11:59 - 12:00) it travelled 6928.203... m
1 min = 60 s
speed = distance/time = 6928.203../60 m/s
= appr 115.5 m/s
At 11:59 , let the horizontal distance of the plane from the observer be x m
then tan30° = 4000/x
x = 4000/tan30° = 6928.203... m
so in 1 min (11:59 - 12:00) it travelled 6928.203... m
1 min = 60 s
speed = distance/time = 6928.203../60 m/s
= appr 115.5 m/s
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.