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Asked by lola

write a rational expression that has a hole at x=-1 and a vertical asymptote at x=2/3
3 years ago

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Answered by mathhelper
f(x) = (x+1)/((x+1)(3x - 2))
or
= (x+1) / (3x^2 + x - 2)
3 years ago
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write a rational expression that has a hole at x=-1 and a vertical asymptote at x=2/3

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