Question

A student holds a water balloon outside of an open window and lets go. The window is 10 meters above the ground, and the balloon is falling under the acceleration of gravity, which is 9.8 m/s^2. There are two equations that can be used to describe its motion over time:

x= x0 + v0t + 1/2 at^2
v= v0 + at
Would the balloon hit the ground before or after 1.0 s of falling? Which equation did you use to decide, and what comparison did you make to determine that it would or would not hit the ground by then?

Use 3 sentences.

Answer 1

in 1 second, it falls 4.9 meters (1/2 at^2)

Answer 2

I did yf = y0 + bot + 1/2at^2 (1)
So 0 = 10m 1/2gt^2
Then t = 2 + 10m/9.8/8^2 = 1.4s.

Answer 3

Not bot but *vot*

Answer 4

We add on to 4.9 meters?

Answer 5

0 = 10 + 0 - (1/2) (9.81) t^2
4.9 t^2 = 10
t = 1.43 seconds in the air before hitting ground
so
it is still in the air after one second, like period :)

Answer 6

and remember if h is up, g is down, negative

Answer 7

Thank you :)

Answer 8

I'm still trying to figure out how biology plays into this question.

Answer 9

Thx

Answer 10

Is anyone still on this cuz I need help still

Answer 11

Y’all I need help