Asked by Jikyung
TV’s are usually measured along the diagonal of the screen. A 52-inch display has a
diagonal that measures 52 inches. If the height of the screen is 15 inches how wide is the TV?
Do we do 52 times 15? Or division? Or something else?
diagonal that measures 52 inches. If the height of the screen is 15 inches how wide is the TV?
Do we do 52 times 15? Or division? Or something else?
Answers
Answered by
Jikyung
Can someone like answer my question please?
Answered by
mathhelper
no, use Pythagoras
w^2 + h^2 = d^2 , width, length , diagonal
w^2 + 15^2 = 52^2
w^2 = 2704 - 225 = 2479
w = √2479 = appr 49.79 inches, I would say 50 inches
w^2 + h^2 = d^2 , width, length , diagonal
w^2 + 15^2 = 52^2
w^2 = 2704 - 225 = 2479
w = √2479 = appr 49.79 inches, I would say 50 inches
Answered by
Jikyung
Alrighty, thanks ma'am/sir.
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