Asked by Aliyah
The half-life of Radon-222 is 3.83 days. How many days will it take for a sample to decay to 69% of its original mass? Round your answer to two decimal places.
2^⁻t/3.83 = .69
ln2^-t/3.83 =ln(.69)
-t/3.83In2=In(.69)
t=3.83(In.69)/In2
t=-2.05032
t=2.05 days
check my work please ..thanks
2^⁻t/3.83 = .69
ln2^-t/3.83 =ln(.69)
-t/3.83In2=In(.69)
t=3.83(In.69)/In2
t=-2.05032
t=2.05 days
check my work please ..thanks
Answers
Answered by
mathhelper
you are correct