Asked by Leyah
The half-life of radon-222 is 3.82 days. If a sample of gas contains 4.38ug of radon-222, how much will remain in the sample after 15.2 days?
Answers
Answered by
DrBob222
k = 0.693/t<sub>1/2</sub>
Substitute k into the following:
ln(No/N) = kt
No = 4.38 ug.
N = solve for this.
k from above.
t = 15.2 days.
Substitute k into the following:
ln(No/N) = kt
No = 4.38 ug.
N = solve for this.
k from above.
t = 15.2 days.
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